Difference between revisions of "Generator Efficiency"
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+ | Here several useful generator equations are derived. | ||
=Electrical Efficiency= | =Electrical Efficiency= | ||
− | + | Electrical efficiency as a fraction input mechanical power that is available as electricity the output terminals. Of course the voltage of the avaialbe power might not be optimal - but thats what switching power supplies are for. | |
<pre> | <pre> | ||
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=Power Efficiency= | =Power Efficiency= | ||
− | For a load that is a multiple of the generator resistance, a fraction of the maximum output power is obtained. If the load equals the generator resistance, then the maximum output power is obtained. | + | For a load that is a multiple of the generator resistance, a fraction of the maximum possible generator output power is obtained. If the load equals the internal generator resistance, then the maximum output power (Pmax) is obtained. |
<pre> | <pre> | ||
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=Maximum Power= | =Maximum Power= | ||
− | + | Its also possible to size a generator based on two fundamental properties of the generator. Here we derive the maximum generator power as a function of rotational velocity omega. | |
<pre> | <pre> |
Revision as of 08:18, 20 April 2007
Here several useful generator equations are derived.
Electrical Efficiency
Electrical efficiency as a fraction input mechanical power that is available as electricity the output terminals. Of course the voltage of the avaialbe power might not be optimal - but thats what switching power supplies are for.
E = Pout / (Pout + Ploss) Pout = I^2 * Rl and Ploss = I^2 * Rm thus E = I^2 * (Rl / (Rl+Rm)) let Rl = k * Rm then E = k/(1+k) for a given desired efficiency keep Rl >= Rm * E/(1-E) some results: k = 4 -> 80% k = 9 -> 90%
Power Efficiency
For a load that is a multiple of the generator resistance, a fraction of the maximum possible generator output power is obtained. If the load equals the internal generator resistance, then the maximum output power (Pmax) is obtained.
Let the power efficiency be: Pe = Pout / Pmax some math... Pe = 4k/(1+k)^2 64% -> k = 4 (80% electrical efficiency) 36% -> k = 9 (90% electrical efficiency)
Maximum Power
Its also possible to size a generator based on two fundamental properties of the generator. Here we derive the maximum generator power as a function of rotational velocity omega.
For a generator / motor: omega = Ks * Vemf (Vemf is back emf) or Vemf = omega/Ks Vm = Vemf - I * Rm (Vm is voltage at terminals) I = Vm / Rl let Rl = Rm for max output power then Vm = Vemf - (Vm/Rm)*Rm or Vm = omega/Ks - Vm so at max output power Vm = omega/2Ks output power is V^2/R so Pmax = Vm^2 / Rm or Pmax = omega^2 / 4 Rm Ks^2 lets define the power constant as Pk = 1/4RmKs^2 so Pmax = Pk * omega^2