Generator Efficiency
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Electrical Efficiency
Efficiency as a fraction input mechanical power that is available at the output terminals:
E = Pout / (Pout + Ploss) . Pout = I^2 * Rl and Ploss = I^2 * Rm thus . E = I^2 * (Rl / (Rl+Rm)) . let Rl = k * Rm then . E = k/(1+k) . for a given desired efficiency keep . Rl >= Rm * E/(1-E) . some results: k = 4 -> 80% k = 9 -> 90%
Power Efficiency
For a load that is a multiple of the genetator resistance, a fraction of the maximum output power is obtained. If the load equals the genetator resistance, then the maxium output power is obtained.
Let the power efficiency be: . Pe = Pout / Pmax . some math... . Pe = 4k/(1+k)^2 . Pe of 64% -> k = 4 (80% electrical efficiency) 36% -> k = 9 (90% lectrical efficiency)