Difference between revisions of "Generator Efficiency"
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=Power Efficiency= | =Power Efficiency= | ||
− | For a load that is a multiple of the | + | For a load that is a multiple of the generator resistance, a fraction of the maximum output power is obtained. If the load equals the generator resistance, then the maximum output power is obtained. |
− | + | <pre> | |
− | + | Let the power efficiency be: | |
− | + | ||
− | + | Pe = Pout / Pmax | |
− | + | ||
− | + | some math... | |
− | + | ||
− | + | Pe = 4k/(1+k)^2 | |
− | + | ||
− | + | 64% -> k = 4 (80% electrical efficiency) | |
+ | 36% -> k = 9 (90% electrical efficiency) | ||
+ | </pre> |
Revision as of 08:12, 20 April 2007
Electrical Efficiency
Efficiency as a fraction input mechanical power that is available at the output terminals:
E = Pout / (Pout + Ploss) . Pout = I^2 * Rl and Ploss = I^2 * Rm thus . E = I^2 * (Rl / (Rl+Rm)) . let Rl = k * Rm then . E = k/(1+k) . for a given desired efficiency keep . Rl >= Rm * E/(1-E) . some results: k = 4 -> 80% k = 9 -> 90%
Power Efficiency
For a load that is a multiple of the generator resistance, a fraction of the maximum output power is obtained. If the load equals the generator resistance, then the maximum output power is obtained.
Let the power efficiency be: Pe = Pout / Pmax some math... Pe = 4k/(1+k)^2 64% -> k = 4 (80% electrical efficiency) 36% -> k = 9 (90% electrical efficiency)